8(v+2)=-3v-28

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Solution for 8(v+2)=-3v-28 equation: 



8(v+2)=-3v-28

We move all terms to the left:

8(v+2)-(-3v-28)=0

We multiply parentheses

8v-(-3v-28)+16=0

We get rid of parentheses

8v+3v+28+16=0

We add all the numbers together, and all the variables

11v+44=0

We move all terms containing v to the left, all other terms to the right

11v=-44

v=-44/11

v=-4

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