5(c-2)=6(c-5)

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Solution for 5(c-2)=6(c-5) equation: 



5(c-2)=6(c-5)

We move all terms to the left:

5(c-2)-(6(c-5))=0

We multiply parentheses

5c-(6(c-5))-10=0



We calculate terms in parentheses: -(6(c-5)), so:

6(c-5)

We multiply parentheses

6c-30

Back to the equation:

-(6c-30)



We get rid of parentheses

5c-6c+30-10=0

We add all the numbers together, and all the variables

-1c+20=0

We move all terms containing c to the left, all other terms to the right

-c=-20

c=-20/-1

c=+20

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