8(v+2)-2v=2(3v+1)-5

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Solution for 8(v+2)-2v=2(3v+1)-5 equation: 



8(v+2)-2v=2(3v+1)-5

We move all terms to the left:

8(v+2)-2v-(2(3v+1)-5)=0

We add all the numbers together, and all the variables

-2v+8(v+2)-(2(3v+1)-5)=0

We multiply parentheses

-2v+8v-(2(3v+1)-5)+16=0



We calculate terms in parentheses: -(2(3v+1)-5), so:

2(3v+1)-5

We multiply parentheses

6v+2-5

We add all the numbers together, and all the variables

6v-3

Back to the equation:

-(6v-3)



We add all the numbers together, and all the variables

6v-(6v-3)+16=0

We get rid of parentheses

6v-6v+3+16=0

We add all the numbers together, and all the variables

19!=0

There is no solution for this equation

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