8(u-3)=4u+8

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Solution for 8(u-3)=4u+8 equation: 



8(u-3)=4u+8

We move all terms to the left:

8(u-3)-(4u+8)=0

We multiply parentheses

8u-(4u+8)-24=0

We get rid of parentheses

8u-4u-8-24=0

We add all the numbers together, and all the variables

4u-32=0

We move all terms containing u to the left, all other terms to the right

4u=32

u=32/4

u=8

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