8(t+2)-8(t+4)=6(t-7)+8

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Solution for 8(t+2)-8(t+4)=6(t-7)+8 equation: 



8(t+2)-8(t+4)=6(t-7)+8

We move all terms to the left:

8(t+2)-8(t+4)-(6(t-7)+8)=0

We multiply parentheses

8t-8t-(6(t-7)+8)+16-32=0



We calculate terms in parentheses: -(6(t-7)+8), so:

6(t-7)+8

We multiply parentheses

6t-42+8

We add all the numbers together, and all the variables

6t-34

Back to the equation:

-(6t-34)



We add all the numbers together, and all the variables

-(6t-34)-16=0

We get rid of parentheses

-6t+34-16=0

We add all the numbers together, and all the variables

-6t+18=0

We move all terms containing t to the left, all other terms to the right

-6t=-18

t=-18/-6

t=+3

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