7(x+3)=5(x-2)

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Solution for 7(x+3)=5(x-2) equation: 



7(x+3)=5(x-2)

We move all terms to the left:

7(x+3)-(5(x-2))=0

We multiply parentheses

7x-(5(x-2))+21=0



We calculate terms in parentheses: -(5(x-2)), so:

5(x-2)

We multiply parentheses

5x-10

Back to the equation:

-(5x-10)



We get rid of parentheses

7x-5x+10+21=0

We add all the numbers together, and all the variables

2x+31=0

We move all terms containing x to the left, all other terms to the right

2x=-31

x=-31/2

x=-15+1/2

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