8(t+2)-4=6(t-7)+8

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Solution for 8(t+2)-4=6(t-7)+8 equation: 



8(t+2)-4=6(t-7)+8

We move all terms to the left:

8(t+2)-4-(6(t-7)+8)=0

We multiply parentheses

8t-(6(t-7)+8)+16-4=0



We calculate terms in parentheses: -(6(t-7)+8), so:

6(t-7)+8

We multiply parentheses

6t-42+8

We add all the numbers together, and all the variables

6t-34

Back to the equation:

-(6t-34)



We add all the numbers together, and all the variables

8t-(6t-34)+12=0

We get rid of parentheses

8t-6t+34+12=0

We add all the numbers together, and all the variables

2t+46=0

We move all terms containing t to the left, all other terms to the right

2t=-46

t=-46/2

t=-23

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