3(c-4)=2(c-1)

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Solution for 3(c-4)=2(c-1) equation: 



3(c-4)=2(c-1)

We move all terms to the left:

3(c-4)-(2(c-1))=0

We multiply parentheses

3c-(2(c-1))-12=0



We calculate terms in parentheses: -(2(c-1)), so:

2(c-1)

We multiply parentheses

2c-2

Back to the equation:

-(2c-2)



We get rid of parentheses

3c-2c+2-12=0

We add all the numbers together, and all the variables

c-10=0

We move all terms containing c to the left, all other terms to the right

c=10

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