4(2g-3)=7(g-2)

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Solution for 4(2g-3)=7(g-2) equation: 



4(2g-3)=7(g-2)

We move all terms to the left:

4(2g-3)-(7(g-2))=0

We multiply parentheses

8g-(7(g-2))-12=0



We calculate terms in parentheses: -(7(g-2)), so:

7(g-2)

We multiply parentheses

7g-14

Back to the equation:

-(7g-14)



We get rid of parentheses

8g-7g+14-12=0

We add all the numbers together, and all the variables

g+2=0

We move all terms containing g to the left, all other terms to the right

g=-2

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