8(p+8)=(8p-12)1/2

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Solution for 8(p+8)=(8p-12)1/2 equation: 



8(p+8)=(8p-12)1/2

We move all terms to the left:

8(p+8)-((8p-12)1/2)=0

We multiply parentheses

8p-((8p-12)1/2)+64=0

We multiply all the terms by the denominator


8p*2)-((8p-12)1+64*2)=0

We add all the numbers together, and all the variables

8p*2)-((8p-12)1=0

Wy multiply elements

16p^2=0

a = 16; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·16·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$p=\frac{-b}{2a}=\frac{0}{32}=0$

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