3(z-8)=2(1-2z)

Solution for 3(z-8)=2(1-2z) equation:

3(z-8)=2(1-2z)

We move all terms to the left:

3(z-8)-(2(1-2z))=0

We add all the numbers together, and all the variables

3(z-8)-(2(-2z+1))=0

We multiply parentheses

3z-(2(-2z+1))-24=0


We calculate terms in parentheses: -(2(-2z+1)), so:

2(-2z+1)

We multiply parentheses

-4z+2

Back to the equation:

-(-4z+2)


We get rid of parentheses

3z+4z-2-24=0

We add all the numbers together, and all the variables

7z-26=0

We move all terms containing z to the left, all other terms to the right

7z=26

z=26/7

z=3+5/7