N-4(2x+3)=2x+6-(8x+2)

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Solution for N-4(2x+3)=2x+6-(8x+2) equation: 



-4(2N+3)=2N+6-(8N+2)

We move all terms to the left:

-4(2N+3)-(2N+6-(8N+2))=0

We multiply parentheses

-8N-(2N+6-(8N+2))-12=0



We calculate terms in parentheses: -(2N+6-(8N+2)), so:

2N+6-(8N+2)

determiningTheFunctionDomain
2N-(8N+2)+6

We get rid of parentheses

2N-8N-2+6

We add all the numbers together, and all the variables

-6N+4

Back to the equation:

-(-6N+4)



We get rid of parentheses

-8N+6N-4-12=0

We add all the numbers together, and all the variables

-2N-16=0

We move all terms containing N to the left, all other terms to the right

-2N=16

N=16/-2

N=-8

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