8(n-1/2)-2(2+3n)=16+8n

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Solution for 8(n-1/2)-2(2+3n)=16+8n equation: 



8(n-1/2)-2(2+3n)=16+8n

We move all terms to the left:

8(n-1/2)-2(2+3n)-(16+8n)=0

We add all the numbers together, and all the variables

8(+n-1/2)-2(3n+2)-(8n+16)=0

We multiply parentheses

8n-6n-(8n+16)-4-1/2*8=0

We get rid of parentheses

8n-6n-8n-16-4-1/2*8=0

We multiply all the terms by the denominator


8n*2*8-6n*2*8-8n*2*8-1-16*2*8-4*2*8=0

We add all the numbers together, and all the variables

8n*2*8-6n*2*8-8n*2*8-321=0

Wy multiply elements

128n*8-96n*8-128n*8-321=0

Wy multiply elements

1024n-768n-1024n-321=0

We add all the numbers together, and all the variables

-768n-321=0

We move all terms containing n to the left, all other terms to the right

-768n=321

n=321/-768

n=-107/256

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