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(5x-72)(6x-96)=0
We multiply parentheses ..
(+30x^2-480x-432x+6912)=0
We get rid of parentheses
30x^2-480x-432x+6912=0
We add all the numbers together, and all the variables
30x^2-912x+6912=0
a = 30; b = -912; c = +6912;
Δ = b2-4ac
Δ = -9122-4·30·6912
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2304}=48$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-912)-48}{2*30}=\frac{864}{60} =14+2/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-912)+48}{2*30}=\frac{960}{60} =16 $
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