8(n+2)=2(n-7)

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Solution for 8(n+2)=2(n-7) equation:



8(n+2)=2(n-7)
We move all terms to the left:
8(n+2)-(2(n-7))=0
We multiply parentheses
8n-(2(n-7))+16=0
We calculate terms in parentheses: -(2(n-7)), so:
2(n-7)
We multiply parentheses
2n-14
Back to the equation:
-(2n-14)
We get rid of parentheses
8n-2n+14+16=0
We add all the numbers together, and all the variables
6n+30=0
We move all terms containing n to the left, all other terms to the right
6n=-30
n=-30/6
n=-5

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