6(v+1)=-4(4v-3)+6v

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Solution for 6(v+1)=-4(4v-3)+6v equation: 



6(v+1)=-4(4v-3)+6v

We move all terms to the left:

6(v+1)-(-4(4v-3)+6v)=0

We multiply parentheses

6v-(-4(4v-3)+6v)+6=0



We calculate terms in parentheses: -(-4(4v-3)+6v), so:

-4(4v-3)+6v

We add all the numbers together, and all the variables

6v-4(4v-3)

We multiply parentheses

6v-16v+12

We add all the numbers together, and all the variables

-10v+12

Back to the equation:

-(-10v+12)



We get rid of parentheses

6v+10v-12+6=0

We add all the numbers together, and all the variables

16v-6=0

We move all terms containing v to the left, all other terms to the right

16v=6

v=6/16

v=3/8

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