8(k+2)-1=6+2k-9

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Solution for 8(k+2)-1=6+2k-9 equation: 



8(k+2)-1=6+2k-9

We move all terms to the left:

8(k+2)-1-(6+2k-9)=0

We add all the numbers together, and all the variables

8(k+2)-(2k-3)-1=0

We multiply parentheses

8k-(2k-3)+16-1=0

We get rid of parentheses

8k-2k+3+16-1=0

We add all the numbers together, and all the variables

6k+18=0

We move all terms containing k to the left, all other terms to the right

6k=-18

k=-18/6

k=-3

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