8(k+2)-1=6+2k+9

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Solution for 8(k+2)-1=6+2k+9 equation: 



8(k+2)-1=6+2k+9

We move all terms to the left:

8(k+2)-1-(6+2k+9)=0

We add all the numbers together, and all the variables

8(k+2)-(2k+15)-1=0

We multiply parentheses

8k-(2k+15)+16-1=0

We get rid of parentheses

8k-2k-15+16-1=0

We add all the numbers together, and all the variables

6k=0

k=0/6

k=0

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