8(i+6)-10-2=3(i-12)+i

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Solution for 8(i+6)-10-2=3(i-12)+i equation: 



8(i+6)-10-2=3(i-12)+i

We move all terms to the left:

8(i+6)-10-2-(3(i-12)+i)=0

We add all the numbers together, and all the variables

8(i+6)-(3(i-12)+i)-12=0

We multiply parentheses

8i-(3(i-12)+i)+48-12=0



We calculate terms in parentheses: -(3(i-12)+i), so:

3(i-12)+i

We add all the numbers together, and all the variables

i+3(i-12)

We multiply parentheses

i+3i-36

We add all the numbers together, and all the variables

4i-36

Back to the equation:

-(4i-36)



We add all the numbers together, and all the variables

8i-(4i-36)+36=0

We get rid of parentheses

8i-4i+36+36=0

We add all the numbers together, and all the variables

4i+72=0

We move all terms containing i to the left, all other terms to the right

4i=-72

i=-72/4

i=-18

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