3(b+4)=2(b-2)

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Solution for 3(b+4)=2(b-2) equation: 



3(b+4)=2(b-2)

We move all terms to the left:

3(b+4)-(2(b-2))=0

We multiply parentheses

3b-(2(b-2))+12=0



We calculate terms in parentheses: -(2(b-2)), so:

2(b-2)

We multiply parentheses

2b-4

Back to the equation:

-(2b-4)



We get rid of parentheses

3b-2b+4+12=0

We add all the numbers together, and all the variables

b+16=0

We move all terms containing b to the left, all other terms to the right

b=-16

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