8(d-4)-4(d-3)=32

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Solution for 8(d-4)-4(d-3)=32 equation: 



8(d-4)-4(d-3)=32

We move all terms to the left:

8(d-4)-4(d-3)-(32)=0

We multiply parentheses

8d-4d-32+12-32=0

We add all the numbers together, and all the variables

4d-52=0

We move all terms containing d to the left, all other terms to the right

4d=52

d=52/4

d=13

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