4x2+6x-4=7

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Solution for 4x2+6x-4=7 equation:



4x^2+6x-4=7
We move all terms to the left:
4x^2+6x-4-(7)=0
We add all the numbers together, and all the variables
4x^2+6x-11=0
a = 4; b = 6; c = -11;
Δ = b2-4ac
Δ = 62-4·4·(-11)
Δ = 212
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{212}=\sqrt{4*53}=\sqrt{4}*\sqrt{53}=2\sqrt{53}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2\sqrt{53}}{2*4}=\frac{-6-2\sqrt{53}}{8} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2\sqrt{53}}{2*4}=\frac{-6+2\sqrt{53}}{8} $

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