8(b-)+3b=-9(b-1)

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Solution for 8(b-)+3b=-9(b-1) equation: 



8(b-)+3b=-9(b-1)

We move all terms to the left:

8(b-)+3b-(-9(b-1))=0

We add all the numbers together, and all the variables

8(+b)+3b-(-9(b-1))=0

We add all the numbers together, and all the variables

3b+8(+b)-(-9(b-1))=0

We multiply parentheses

3b+8b-(-9(b-1))=0



We calculate terms in parentheses: -(-9(b-1)), so:

-9(b-1)

We multiply parentheses

-9b+9

Back to the equation:

-(-9b+9)



We add all the numbers together, and all the variables

11b-(-9b+9)=0

We get rid of parentheses

11b+9b-9=0

We add all the numbers together, and all the variables

20b-9=0

We move all terms containing b to the left, all other terms to the right

20b=9

b=9/20

b=9/20

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