(3y+20)=(5y-16)=74

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Solution for (3y+20)=(5y-16)=74 equation: 



(3y+20)=(5y-16)=74

We move all terms to the left:

(3y+20)-((5y-16))=0

We get rid of parentheses

3y-((5y-16))+20=0



We calculate terms in parentheses: -((5y-16)), so:

(5y-16)

We get rid of parentheses

5y-16

Back to the equation:

-(5y-16)



We get rid of parentheses

3y-5y+16+20=0

We add all the numbers together, and all the variables

-2y+36=0

We move all terms containing y to the left, all other terms to the right

-2y=-36

y=-36/-2

y=+18

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