8(b+2)=64

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Solution for 8(b+2)=64 equation: 



8(b+2)=64

We move all terms to the left:

8(b+2)-(64)=0

We multiply parentheses

8b+16-64=0

We add all the numbers together, and all the variables

8b-48=0

We move all terms containing b to the left, all other terms to the right

8b=48

b=48/8

b=6

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