8(8-2b)=128

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Solution for 8(8-2b)=128 equation: 



8(8-2b)=128

We move all terms to the left:

8(8-2b)-(128)=0

We add all the numbers together, and all the variables

8(-2b+8)-128=0

We multiply parentheses

-16b+64-128=0

We add all the numbers together, and all the variables

-16b-64=0

We move all terms containing b to the left, all other terms to the right

-16b=64

b=64/-16

b=-4

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