8(6y+9)=4(4y-10)=6

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Solution for 8(6y+9)=4(4y-10)=6 equation: 



8(6y+9)=4(4y-10)=6

We move all terms to the left:

8(6y+9)-(4(4y-10))=0

We multiply parentheses

48y-(4(4y-10))+72=0



We calculate terms in parentheses: -(4(4y-10)), so:

4(4y-10)

We multiply parentheses

16y-40

Back to the equation:

-(16y-40)



We get rid of parentheses

48y-16y+40+72=0

We add all the numbers together, and all the variables

32y+112=0

We move all terms containing y to the left, all other terms to the right

32y=-112

y=-112/32

y=-3+1/2

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