4(s-7)=5(s-3)+2

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Solution for 4(s-7)=5(s-3)+2 equation: 



4(s-7)=5(s-3)+2

We move all terms to the left:

4(s-7)-(5(s-3)+2)=0

We multiply parentheses

4s-(5(s-3)+2)-28=0



We calculate terms in parentheses: -(5(s-3)+2), so:

5(s-3)+2

We multiply parentheses

5s-15+2

We add all the numbers together, and all the variables

5s-13

Back to the equation:

-(5s-13)



We get rid of parentheses

4s-5s+13-28=0

We add all the numbers together, and all the variables

-1s-15=0

We move all terms containing s to the left, all other terms to the right

-s=15

s=15/-1

s=-15

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