8(6+4x)+24=16+2(x+7)

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Solution for 8(6+4x)+24=16+2(x+7) equation: 



8(6+4x)+24=16+2(x+7)

We move all terms to the left:

8(6+4x)+24-(16+2(x+7))=0

We add all the numbers together, and all the variables

8(4x+6)-(16+2(x+7))+24=0

We multiply parentheses

32x-(16+2(x+7))+48+24=0



We calculate terms in parentheses: -(16+2(x+7)), so:

16+2(x+7)

determiningTheFunctionDomain
2(x+7)+16

We multiply parentheses

2x+14+16

We add all the numbers together, and all the variables

2x+30

Back to the equation:

-(2x+30)



We add all the numbers together, and all the variables

32x-(2x+30)+72=0

We get rid of parentheses

32x-2x-30+72=0

We add all the numbers together, and all the variables

30x+42=0

We move all terms containing x to the left, all other terms to the right

30x=-42

x=-42/30

x=-1+2/5

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