3(x+1)x2=x2+12

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Solution for 3(x+1)x2=x2+12 equation: 



3(x+1)x2=x2+12

We move all terms to the left:

3(x+1)x2-(x2+12)=0

We add all the numbers together, and all the variables

-(+x^2+12)+3(x+1)x2=0

We multiply parentheses

-(+x^2+12)+3x^3+3x^2=0

We get rid of parentheses

-x^2+3x^3+3x^2-12=0

We do not support expression: x^3

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