8(5x-4)-1=2(x+3)-7

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Solution for 8(5x-4)-1=2(x+3)-7 equation: 



8(5x-4)-1=2(x+3)-7

We move all terms to the left:

8(5x-4)-1-(2(x+3)-7)=0

We multiply parentheses

40x-(2(x+3)-7)-32-1=0



We calculate terms in parentheses: -(2(x+3)-7), so:

2(x+3)-7

We multiply parentheses

2x+6-7

We add all the numbers together, and all the variables

2x-1

Back to the equation:

-(2x-1)



We add all the numbers together, and all the variables

40x-(2x-1)-33=0

We get rid of parentheses

40x-2x+1-33=0

We add all the numbers together, and all the variables

38x-32=0

We move all terms containing x to the left, all other terms to the right

38x=32

x=32/38

x=16/19

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