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190=4b^2-6
We move all terms to the left:
190-(4b^2-6)=0
We get rid of parentheses
-4b^2+6+190=0
We add all the numbers together, and all the variables
-4b^2+196=0
a = -4; b = 0; c = +196;
Δ = b2-4ac
Δ = 02-4·(-4)·196
Δ = 3136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3136}=56$$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-56}{2*-4}=\frac{-56}{-8} =+7 $$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+56}{2*-4}=\frac{56}{-8} =-7 $
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