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8(5-x)=1/2x
We move all terms to the left:
8(5-x)-(1/2x)=0
Domain of the equation: 2x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
8(-1x+5)-(+1/2x)=0
We multiply parentheses
-8x-(+1/2x)+40=0
We get rid of parentheses
-8x-1/2x+40=0
We multiply all the terms by the denominator
-8x*2x+40*2x-1=0
Wy multiply elements
-16x^2+80x-1=0
a = -16; b = 80; c = -1;
Δ = b2-4ac
Δ = 802-4·(-16)·(-1)
Δ = 6336
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{6336}=\sqrt{576*11}=\sqrt{576}*\sqrt{11}=24\sqrt{11}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(80)-24\sqrt{11}}{2*-16}=\frac{-80-24\sqrt{11}}{-32} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(80)+24\sqrt{11}}{2*-16}=\frac{-80+24\sqrt{11}}{-32} $
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