5(x+3)-(x-4)=3(x-2)

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Solution for 5(x+3)-(x-4)=3(x-2) equation: 



5(x+3)-(x-4)=3(x-2)

We move all terms to the left:

5(x+3)-(x-4)-(3(x-2))=0

We multiply parentheses

5x-(x-4)-(3(x-2))+15=0

We get rid of parentheses

5x-x-(3(x-2))+4+15=0



We calculate terms in parentheses: -(3(x-2)), so:

3(x-2)

We multiply parentheses

3x-6

Back to the equation:

-(3x-6)



We add all the numbers together, and all the variables

4x-(3x-6)+19=0

We get rid of parentheses

4x-3x+6+19=0

We add all the numbers together, and all the variables

x+25=0

We move all terms containing x to the left, all other terms to the right

x=-25

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