8(4x-7)+6(x-2)=8x-4x

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Solution for 8(4x-7)+6(x-2)=8x-4x equation: 



8(4x-7)+6(x-2)=8x-4x

We move all terms to the left:

8(4x-7)+6(x-2)-(8x-4x)=0

We add all the numbers together, and all the variables

8(4x-7)+6(x-2)-(+4x)=0

We multiply parentheses

32x+6x-(+4x)-56-12=0

We get rid of parentheses

32x+6x-4x-56-12=0

We add all the numbers together, and all the variables

34x-68=0

We move all terms containing x to the left, all other terms to the right

34x=68

x=68/34

x=2

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