-(v-6)=2(5v-5)-3v

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Solution for -(v-6)=2(5v-5)-3v equation: 



-(v-6)=2(5v-5)-3v

We move all terms to the left:

-(v-6)-(2(5v-5)-3v)=0

We get rid of parentheses

-v-(2(5v-5)-3v)+6=0



We calculate terms in parentheses: -(2(5v-5)-3v), so:

2(5v-5)-3v

We add all the numbers together, and all the variables

-3v+2(5v-5)

We multiply parentheses

-3v+10v-10

We add all the numbers together, and all the variables

7v-10

Back to the equation:

-(7v-10)



We add all the numbers together, and all the variables

-1v-(7v-10)+6=0

We get rid of parentheses

-1v-7v+10+6=0

We add all the numbers together, and all the variables

-8v+16=0

We move all terms containing v to the left, all other terms to the right

-8v=-16

v=-16/-8

v=+2

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