8(4x+6)-58=2(7x+31)

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Solution for 8(4x+6)-58=2(7x+31) equation: 



8(4x+6)-58=2(7x+31)

We move all terms to the left:

8(4x+6)-58-(2(7x+31))=0

We multiply parentheses

32x-(2(7x+31))+48-58=0



We calculate terms in parentheses: -(2(7x+31)), so:

2(7x+31)

We multiply parentheses

14x+62

Back to the equation:

-(14x+62)



We add all the numbers together, and all the variables

32x-(14x+62)-10=0

We get rid of parentheses

32x-14x-62-10=0

We add all the numbers together, and all the variables

18x-72=0

We move all terms containing x to the left, all other terms to the right

18x=72

x=72/18

x=4

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