4x-2(3-x)=6(x-1)

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Solution for 4x-2(3-x)=6(x-1) equation: 



4x-2(3-x)=6(x-1)

We move all terms to the left:

4x-2(3-x)-(6(x-1))=0

We add all the numbers together, and all the variables

4x-2(-1x+3)-(6(x-1))=0

We multiply parentheses

4x+2x-(6(x-1))-6=0



We calculate terms in parentheses: -(6(x-1)), so:

6(x-1)

We multiply parentheses

6x-6

Back to the equation:

-(6x-6)



We add all the numbers together, and all the variables

6x-(6x-6)-6=0

We get rid of parentheses

6x-6x+6-6=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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