8(4v-1)-12v=111(2v-6)

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Solution for 8(4v-1)-12v=111(2v-6) equation: 



8(4v-1)-12v=111(2v-6)

We move all terms to the left:

8(4v-1)-12v-(111(2v-6))=0

We add all the numbers together, and all the variables

-12v+8(4v-1)-(111(2v-6))=0

We multiply parentheses

-12v+32v-(111(2v-6))-8=0



We calculate terms in parentheses: -(111(2v-6)), so:

111(2v-6)

We multiply parentheses

222v-666

Back to the equation:

-(222v-666)



We add all the numbers together, and all the variables

20v-(222v-666)-8=0

We get rid of parentheses

20v-222v+666-8=0

We add all the numbers together, and all the variables

-202v+658=0

We move all terms containing v to the left, all other terms to the right

-202v=-658

v=-658/-202

v=3+26/101

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