10x-2(x-3)=8(x+1)+2

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Solution for 10x-2(x-3)=8(x+1)+2 equation: 



10x-2(x-3)=8(x+1)+2

We move all terms to the left:

10x-2(x-3)-(8(x+1)+2)=0

We multiply parentheses

10x-2x-(8(x+1)+2)+6=0



We calculate terms in parentheses: -(8(x+1)+2), so:

8(x+1)+2

We multiply parentheses

8x+8+2

We add all the numbers together, and all the variables

8x+10

Back to the equation:

-(8x+10)



We add all the numbers together, and all the variables

8x-(8x+10)+6=0

We get rid of parentheses

8x-8x-10+6=0

We add all the numbers together, and all the variables

-4!=0

There is no solution for this equation

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