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5x^2=7605
We move all terms to the left:
5x^2-(7605)=0
a = 5; b = 0; c = -7605;
Δ = b2-4ac
Δ = 02-4·5·(-7605)
Δ = 152100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{152100}=390$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-390}{2*5}=\frac{-390}{10} =-39 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+390}{2*5}=\frac{390}{10} =39 $
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