8(4-x)=7x+

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Solution for 8(4-x)=7x+ equation: 



8(4-x)=7x+

We move all terms to the left:

8(4-x)-(7x+)=0

We add all the numbers together, and all the variables

8(-1x+4)-(+7x)=0

We multiply parentheses

-8x-(+7x)+32=0

We get rid of parentheses

-8x-7x+32=0

We add all the numbers together, and all the variables

-15x+32=0

We move all terms containing x to the left, all other terms to the right

-15x=-32

x=-32/-15

x=2+2/15

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