39=(2x+1)+(2x+3)+(2x+5)

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Solution for 39=(2x+1)+(2x+3)+(2x+5) equation: 



39=(2x+1)+(2x+3)+(2x+5)

We move all terms to the left:

39-((2x+1)+(2x+3)+(2x+5))=0



We calculate terms in parentheses: -((2x+1)+(2x+3)+(2x+5)), so:

(2x+1)+(2x+3)+(2x+5)

We get rid of parentheses

2x+2x+2x+1+3+5

We add all the numbers together, and all the variables

6x+9

Back to the equation:

-(6x+9)



We get rid of parentheses

-6x-9+39=0

We add all the numbers together, and all the variables

-6x+30=0

We move all terms containing x to the left, all other terms to the right

-6x=-30

x=-30/-6

x=+5

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