8(4-x)+x=-6(3+x)

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Solution for 8(4-x)+x=-6(3+x) equation: 



8(4-x)+x=-6(3+x)

We move all terms to the left:

8(4-x)+x-(-6(3+x))=0

We add all the numbers together, and all the variables

8(-1x+4)+x-(-6(x+3))=0

We add all the numbers together, and all the variables

x+8(-1x+4)-(-6(x+3))=0

We multiply parentheses

x-8x-(-6(x+3))+32=0



We calculate terms in parentheses: -(-6(x+3)), so:

-6(x+3)

We multiply parentheses

-6x-18

Back to the equation:

-(-6x-18)



We add all the numbers together, and all the variables

-7x-(-6x-18)+32=0

We get rid of parentheses

-7x+6x+18+32=0

We add all the numbers together, and all the variables

-1x+50=0

We move all terms containing x to the left, all other terms to the right

-x=-50

x=-50/-1

x=+50

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