8(4+c)=42

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Solution for 8(4+c)=42 equation: 



8(4+c)=42

We move all terms to the left:

8(4+c)-(42)=0

We add all the numbers together, and all the variables

8(c+4)-42=0

We multiply parentheses

8c+32-42=0

We add all the numbers together, and all the variables

8c-10=0

We move all terms containing c to the left, all other terms to the right

8c=10

c=10/8

c=1+1/4

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