3(y-10)+1=19(y-8)

Solution for 3(y-10)+1=19(y-8) equation:

3(y-10)+1=19(y-8)

We move all terms to the left:

3(y-10)+1-(19(y-8))=0

We multiply parentheses

3y-(19(y-8))-30+1=0


We calculate terms in parentheses: -(19(y-8)), so:

19(y-8)

We multiply parentheses

19y-152

Back to the equation:

-(19y-152)


We add all the numbers together, and all the variables

3y-(19y-152)-29=0

We get rid of parentheses

3y-19y+152-29=0

We add all the numbers together, and all the variables

-16y+123=0

We move all terms containing y to the left, all other terms to the right

-16y=-123

y=-123/-16

y=7+11/16