8(4+2m)=128

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Solution for 8(4+2m)=128 equation: 



8(4+2m)=128

We move all terms to the left:

8(4+2m)-(128)=0

We add all the numbers together, and all the variables

8(2m+4)-128=0

We multiply parentheses

16m+32-128=0

We add all the numbers together, and all the variables

16m-96=0

We move all terms containing m to the left, all other terms to the right

16m=96

m=96/16

m=6

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