5(2x+3)=3(4x+1)-2(3x+3)

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Solution for 5(2x+3)=3(4x+1)-2(3x+3) equation: 



5(2x+3)=3(4x+1)-2(3x+3)

We move all terms to the left:

5(2x+3)-(3(4x+1)-2(3x+3))=0

We multiply parentheses

10x-(3(4x+1)-2(3x+3))+15=0



We calculate terms in parentheses: -(3(4x+1)-2(3x+3)), so:

3(4x+1)-2(3x+3)

We multiply parentheses

12x-6x+3-6

We add all the numbers together, and all the variables

6x-3

Back to the equation:

-(6x-3)



We get rid of parentheses

10x-6x+3+15=0

We add all the numbers together, and all the variables

4x+18=0

We move all terms containing x to the left, all other terms to the right

4x=-18

x=-18/4

x=-4+1/2

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