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4/5(2s+5)-4=1
We move all terms to the left:
4/5(2s+5)-4-(1)=0
Domain of the equation: 5(2s+5)!=0We add all the numbers together, and all the variables
s∈R
4/5(2s+5)-5=0
We multiply all the terms by the denominator
-5*5(2s+5)+4=0
Wy multiply elements
-25s(2+4=0
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