8(3y+5)-35=30y

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Solution for 8(3y+5)-35=30y equation: 



8(3y+5)-35=30y

We move all terms to the left:

8(3y+5)-35-(30y)=0

We add all the numbers together, and all the variables

-30y+8(3y+5)-35=0

We multiply parentheses

-30y+24y+40-35=0

We add all the numbers together, and all the variables

-6y+5=0

We move all terms containing y to the left, all other terms to the right

-6y=-5

y=-5/-6

y=5/6

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